Write a program to find sum of first n natural numbers without using loop draw the flowchart. Each call adds the current value of n to the sum of smaller values, effectively building the result in a top-down manner. The reasoning behind the latter is that it takes up a lot of heap space, even before starting any calculations. But I cannot use any loops (like for, do-while etc. Conclusion Both approaches provided the same result—the sum of the n natural numbers. May 28, 2018 · 1 I was given the task of writing a method in Java that computes the sum of the first N positive numbers. Sep 5, 2025 · The recursion continues until the base case is reached, where n it becomes 0 and returns 0 to stop further calls. I cannot use multiplication either. Before going to the source codes, I’ve presented an algorithm (plus pseudo code) to find the sum of first N natural numbers. Jun 16, 2022 · In C programming, the sum of first N natural numbers can be found by either using loop or without loop. Finally, as the recursive calls return back, all values are added step by step to produce the total sum. . Your turn: Modify the above program to find the sum of natural numbers using the formula below. It’s a more efficient method since it avoids the overhead of a loop and an intermediate variable. ), and I cannot use iteration either. Sep 4, 2025 · [Another Approach] Using Recursion -O (n) and O (n) Space In this approach, we use recursion to find the sum of the first n natural numbers. Mar 13, 2024 · Display sum End Flowchart This approach directly applies the formula n (n+1)2 to calculate the sum of the first n natural numbers without the need for iteration. Code to find the sum of natural numbers up to n using recursion. Nov 21, 2019 · The above program logic - How to calculate sum of first N natural numbers without using loop given below ! S=n× (n+1)/2; Were, S is a variable to store the result of Sum of first N natural number We could have solved the above problem without using a loop by using the following formula. The function calls itself with (n-1) until it reaches the base case of n = 1. This algorithm can be used to write code for the given problem in any other programming language as well. n*(n+1)/2 For example, if n = 16, the sum would be (16*17)/2 = 136. stir lhj hpx duxnhg myhzht zhmi rrg yvcqa lnctb brh